Question on: JAMB Physics - 2006
If two charged plates are maintained at a potential difference of 3 kv, the work done in taking a charge of 600 µC across the field is?
A
0.8 J
B
1.8 J
C
9.0 J
D
18.0 J
Ask EduPadi AI for a detailed answer
Correct Option: B
Work done = product of the charge Q, and the p.d V.
(i)/e work done = Q.V = 600 x 10-6 x 3.0 x 10-3 = 1.8 J.
Add your answer
Please share this, thanks!
No responses